 | Charles Vyse - 1785 - 350 halaman
...In. 8", 4,", by 6 Feet, 4 In. 8', 6"". PROBLEM II. To find the Area of a Parallelogram, whether it Se a Square, a Rectangle, a .Rhombus, or a Rhomboides....perpendicular Breadth, and the Product will be the Area.' If the Area of a Piece of Ground, in Yards, is divided by 4840 (the Number of fquare Yards in one Acre)... | |
 | Charles Vyse - 1806 - 342 halaman
...7"", by 8 Feet, 6', 7". (I2j Multiply 46 Feet, 6 In. 8', 4'", by 6 Feet, 4 In.8', &". t PROBLEM II. To find the Area of a Parallelogram, whether it be...perpendicular Breadth, and the Product will be the Area. If the Area in Links be divided by 100000 (the Number of square Links in one Acre) the Quotient will... | |
 | Charles Hutton - 1807 - 464 halaman
...the rectangle is said to contain, which in the present case is 12. PROBLEM I. To find the Area of any Parallelogram ,- "whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the... | |
 | Samuel Webber - 1808 - 466 halaman
...fathom 16i feet. or } . . 5$ yards } 1 pole or rod 40 poles 1 furlong SQJJARE MEASURES. PR0BLEM I. Tojmd the area of a parallelogram ; whether it be a square^ a rectangle, a rhombus, or a rhomboid. RULE.* Multiply the length by the breadth, or a perpendicular height, and the product will... | |
 | Peter Nicholson - 1809 - 426 halaman
...Arithmetical Contents. MENSURATION. Of Superficies. Definition . . . . .153 I. To find the area of any parallelogram, whether „ it be a square, a rectangle, a rhombus, or a rhomboidcs . . . . 154 II. To find the ar«a of a triangle . . 156 III. To find the area of a triangle,... | |
 | Charles Hutton - 1811 - 494 halaman
...rectangle is said to contain, which in the present case is 12. PROBLEM I. 3*0 fold the Area of any Parallelogram ; whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the... | |
 | William Jillard Hort - 1822 - 308 halaman
...AB, the height of the tower will be found equal to 223-3 lect. MENSURATION OF PLANE FIGURES. Probltm. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. Rule 1. Multiply the length by the perpendicular breadth, and the product will be the area.... | |
 | Charles Hutton - 1822 - 616 halaman
...rectangle is> said to contain which in the present case is 12. PROBLEM f. To find Ike Area, of any Parallelogram ; whether it be a Square, a Rectangle, a Rhombus, or a Rhomboid. MULTIPLY the length by the perpendicular breadth, or height, and the product will be the... | |
 | John Nicholson - 1825 - 822 halaman
...triangles, are to each other, as the squares of their like sides. MENSURATION OF SUPERFICIES. Prol. 1. To find the area of a parallelogram: whether it be a square, a rectangle, a rhombus, or a rhomboid. Multiply the length by the breadth, or perpendicular height, and the product will be the... | |
 | Peter Nicholson - 1825 - 1046 halaman
...altititude of the square. Hence we have the following rule for any parallelogram whatever. Prob. 1. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboïdes. Multiply the length by the perpendicular height, and (he product will be the area. Ex.... | |
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PROBLEM I. To find the area of a parallelogram; whether it be a square, a rectangle, a rhombus, or a rhomboides. RULE.* Multiply the length by the perpendicular height, and the product will be the area. 
