 | John Dougall - 1810 - 554 halaman
...two right angles, or two thirds of one right angle. PROP. VIII. fig. 21. The sum of all the interior angles of a polygon is equal to twice as many right angles, wanting four, as the figure has sides. Let the figure ABCDEF, be a polygon of six sides, that is, a... | |
 | Thomas Leybourn - 1814 - 420 halaman
...Hence, by adopting the notation in the question, we have But the sum of the angles of any polygon being equal to twice as many right angles as the polygon has sides, less four; the sum of all the angles of the polygon will be equal to an even number of right angles, and consequently... | |
 | John Radford Young - 1827 - 228 halaman
...to say, the sum of the angles of the polygon, together with those about the point within . it, are equal to twice as many right angles as the polygon has sides ; but those angles which are' about the point, amount to four right angles, (Prop. VI. Cor. 2.) deducting... | |
 | Adrien Marie Legendre - 1836 - 394 halaman
...figure has sides, wanting four right angles. Hence, the interior angles plus four right .. -i angles, is equal to twice as many right angles as the polygon has aides, and consequently, equal to the sum of the interior angles plus the exterior angles. Taking from... | |
 | Nathan Scholfield - 1845 - 894 halaman
...of each as there arc sides of the polygon ; hence, the sum of all the interior and exterior angles is equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles is equal to two right angles, taken as many times, less two,... | |
 | William Scott - 1845 - 288 halaman
...end ought to coincide. Also, the sum of all the angles, together with four right angles, ought to be equal to twice as many right angles as the polygon has sides (Eue. i. 32. cor.). To find the angle contained by two straight lines conceived to be drawn from a... | |
 | Sir J. Butler Williams - 1846 - 368 halaman
...of all the interior angles of the polygon formed by joining the stations by straight lines will be equal to twice as many right angles as the polygon has sides, wanting 4 right angles (Euc. Cor. 32, I.) Thus, if the figure have 3 sides, the sum of the interior... | |
 | George Roberts Perkins - 1847 - 326 halaman
...exterior angles is equal to four right angles (Prop. xxm) ; therefore the sum of all the interior angles is equal to twice as many right angles as the polygon has sides, wanting four right angles. Cor. 1. Jn any triangle, the sum of all the three angles is equal to two... | |
 | Charles William Hackley - 1847 - 248 halaman
...being equal to the same in another, the triangles are equal. THEOREM XVI. The sum of all the inward angles of a polygon is equal to twice as many right angles, wanting four, as the figure has sides. Let ABODE be any figure ; then the sum of all its inward angles,... | |
 | Charles Davies - 1849 - 372 halaman
...of each as there are sides of the polygon : hence, the sum of all the interior and exterior angles is equal to twice as many right angles as the polygon has sides. Again, the sum of all tho interior angles is equal to two right angles, taken as many times, less two,... | |
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The sum of the interior angles of a polygon is equal to twice as many right angles as the polygon has sides, less four right angles. 
