A handy book for the calculation of strains in girders and similar structures, and their strength1868 |
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Halaman 31
... unloaded boom may be termed a " pair ; " + if these make equal angles with the boom they are equally strained . 95. If both booms be loaded , then- ( a ) in a warren ( zig - zag or single triangle ) girder there will be no " pairs ...
... unloaded boom may be termed a " pair ; " + if these make equal angles with the boom they are equally strained . 95. If both booms be loaded , then- ( a ) in a warren ( zig - zag or single triangle ) girder there will be no " pairs ...
Halaman 32
... unloaded boom . WEB . - For the strain on any pair ( 94 ) of diagonals forming an apex on the unloaded boom , - Multiply the shearing force ( S Hz in the formulæ , or the ordinate in the diagram , for the case 34 to 52 ) , developed ...
... unloaded boom . WEB . - For the strain on any pair ( 94 ) of diagonals forming an apex on the unloaded boom , - Multiply the shearing force ( S Hz in the formulæ , or the ordinate in the diagram , for the case 34 to 52 ) , developed ...
Halaman 33
... boom in a whole girder ( A B , fig . 40 , for instance , ) will be equal to the strain in the bay ( CD ) of the ... unloaded boom ( CD , fig . 41 , for instance ) , -Divide the moment of rupture ( Mr in the formulæ , or the ordi ...
... boom in a whole girder ( A B , fig . 40 , for instance , ) will be equal to the strain in the bay ( CD ) of the ... unloaded boom ( CD , fig . 41 , for instance ) , -Divide the moment of rupture ( Mr in the formulæ , or the ordi ...
Halaman 34
... loaded or unloaded boom will be given ( 97 ) by the ordinate to that polygon taken at the opposite apex . ( See also 106. ) For the diagonals the shearing forces may be taken directly from the diagram for the case ( 34 to 52 ) drawn to ...
... loaded or unloaded boom will be given ( 97 ) by the ordinate to that polygon taken at the opposite apex . ( See also 106. ) For the diagonals the shearing forces may be taken directly from the diagram for the case ( 34 to 52 ) drawn to ...
Halaman 35
... unloaded boom take the ordinate to the circumscribed polygon , * at the centre of the bay ; and for any bay ( as E H ) of the loaded boom take the ordinate to the inscribed polygon * at the centre of the bay . If the ordi nates ...
... unloaded boom take the ordinate to the circumscribed polygon , * at the centre of the bay ; and for any bay ( as E H ) of the loaded boom take the ordinate to the inscribed polygon * at the centre of the bay . If the ordi nates ...
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A Handy Book for the Calculation of Strains in Girders and Similar ... William Humber Pratinjau terbatas - 2023 |
Istilah dan frasa umum
abutment angle apices arch architect Assoc bars Beam of Uniform Bridge and Girder calculated Cast and Wrought-Iron Chap Civil Engineers cloth compression contrary flexure 23 curve diagonal diagram DIAGRAM.-Let A B Ditto EATON HODGKINSON Engineer's equal fixed flange formulæ give the moments horizontal inclined length Inst Iron John Hawkshaw joint Lattice Girders loaded boom Loaded uniformly maximum mid-span Modern Engineering moments of rupture moving load numerous woodcuts opposite apex Outfall Sewer parabola PETER BARLOW Plates points of contrary polygon Practical Treatise Record of Modern resistance River Lea rivets secant Semi-beam Semi-girder shearing force spandril STRENGTH OF MATERIALS strut system of triangulation Tables tangent tension THOMAS TREDGOLD Timber tons Treatise on Cast triangles uniformly distributed uniformly Loaded unit of length unloaded boom upper boom valuable vertical distances volume W. H. Barlow Waterloo Bridge weight WILLIAM HUMBER Woodcuts دو دو
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